Cameron Rector wrote:
> Rodger,
> Thanks for the input however, I believe the last address for the 2532
> is FFFh. The 2532 is a 32k device arranged as 12bit address 8bit data or
> 4096x8=32k.
> I'm a little rusty at this but I also think that 7FFh = 2048 and 4096 =
> FFFh.
That's what happens when I try to calculate addresses in my head instead
of actually looking it up. Sorry about that.
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Received on Mon Oct 2 02:46:32 2006
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