At 02:51 PM 12/20/99 -0500, you wrote:
> > >so E = Q * V = C * V^2...
> >
> > Whoa! That's not quite right, you're off by a factor of 2.
> > ...(hint, I posted this a week ago)...but, so here's the *real*
> derivation...
> >
> > E = 1/2 * C * V^2 ; where V is voltage across cap at the steady state.
>
>The energy/work needed to charge a cap is dependent on how it is charged.
>(see numerous papers on minimizing energy consumption in digital circuits.)
>
>In any case, it's the order of magnitude, not the prepended constant that's
>important... :)
Agreed. In this case we're talking huge capacitors, so the 1/2 does not
factor in much. If it were for .18 micron cmos gate designs however, then
the 1/2 factors in... ;-)
Hey, i was just splitting hairs...LOL.
-anders.
(In real life I'm a digital designer, I only play a physicist on TV.)
Received on Mon Dec 20 14:37:23 1999
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