Re: Bad monitor discharge instructions

> > From: Mark Spaeth [mailto:mspaeth@arcade.ne.mediaone.net]
> > Sent: Monday, December 20, 1999 11:03 AM
> > To: vectorlist@lists.cc.utexas.edu
> > Subject: Re: Bad monitor discharge instructions
> >
> > so E = Q * V = C * V^2...
> >
> > So assuming your .001 F measurement is correct, and using V=20,000
> > E = 400,000J Hmmm... that'll keep you warm at night...
>
> Hey Mark,
>
> Jeez, you take the 'mit' out of your address and you automatically
> became less smart ;-) ;-)
>
> John's measurement was 0.001uF, the 102 was the giveaway. This
> gives you 0.4J. The math is left to the student.

Bah... it was late at night, and he left off the 'u'...

(and I wasn't even replying to the post with his numbers in it! :)
Received on Mon Dec 20 13:48:00 1999